### Find if two rectangles overlap

Given two rectangles, find if the given two rectangles overlap or not.
Note that a rectangle can be represented by two coordinates, top left and bottom right. So mainly we are given following four coordinates.
l1: Top Left coordinate of first rectangle.
r1: Bottom Right coordinate of first rectangle.
l2: Top Left coordinate of second rectangle.
r2: Bottom Right coordinate of second rectangle.
We need to write a function bool doOverlap(l1, r1, l2, r2) that returns true if the two given rectangles overlap.
One solution is to one by one pick all points of one rectangle and see if the point lies inside the other rectangle or not. This can be done using the algorithm discussed here.
Following is a simpler approach. Two rectangles do not overlap if one of the following conditions is true.
1) One rectangle is above top edge of other rectangle.
2) One rectangle is on left side of left edge of other rectangle.
We need to check above cases to find out if given rectangles overlap or not. Following is C++ implementation of the above approach.
 `#include` `struct` `Point` `{` `    ``int` `x, y;` `};` `// Returns true if two rectangles (l1, r1) and (l2, r2) overlap` `bool` `doOverlap(Point l1, Point r1, Point l2, Point r2)` `{` `    ``// If one rectangle is on left side of other` `    ``if` `(l1.x > r2.x || l2.x > r1.x)` `        ``return` `false``;` `    ``// If one rectangle is above other` `    ``if` `(l1.y < r2.y || l2.y < r1.y)` `        ``return` `false``;` `    ``return` `true``;` `}`

### C Questions

C Questions
C Questions

Note : All the programs are tested under Turbo C/C++ compilers.
It is assumed that,
Programs run under DOS environment, The underlying machine is an x86 system, Program is compiled using Turbo C/C++ compiler.
The program output may depend on the information based on this assumptions (for example sizeof(int) == 2 may be assumed).
Predict the output or error(s) for the following:

void main()
{
int const * p=5; printf("%d",++(*p));
}
Compiler error: Cannot modify a constant value.
Explanation:
p is a pointer to a "constant integer". But we tried to change the value of the "constant integer".
main()
{
char s[ ]="man"; int i;
for(i=0;s[ i ];i++)
printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]);
}
aaaa nnnn
Explanation

### Zoho Interview | Set 1 (Advanced Programming Round)

Third Round: (Advanced Programming Round) Here they asked us to create a “Railway reservation system” and gave us 4 modules. The modules were:
1. Booking
2. Availability checking
3. Cancellation
4. Prepare chart
We were asked to create the modules for representing each data first and to continue with the implementation phase.

My Solution :